List of known erratum

During the summer of 2009, an updated version of the text was produced that corrected the errors found to date. The following list is based on the book available on lulu.com

Page 11, The formula for i₁ and R_eq in the top half of the page should have (N₁/N₂)² in them. (This is inverted from what is shown in the text.)
Page 14, The value of R_s at the bottom of the page should be 0.01 Ohms.
Page 15, The value of R_m at the top of the page should be 0.01 Ohms.
Page 23, In the middle of the second paragraph, the expression `` V<sub>th</sub>, (I<sub>N</sub>/R<sub>N</sub>)'' should be ``V_th, (I_N * R_N)''.
Page 92, The second equation (near the top of the page) should be tan(phi_L) -> (omega omega_LR)/(omega_LC^2) and in the following equation, the limit should go to pi (180 degrees).
Page 93, In figure 3.14, the Bode plot is reversed left-to-right.
Page 131, in formula 4.11, the n in the exponential should be an m.
Page 164, formulas for i_out and V_out at the bottom of the page. Both formulas should be over R_C+R_L
Page 166, in the middle of the page, the values for R₁ should be 10.4kOhm and R₂ should be 1.11kOhm. These change then impact the calculation following. We find that C₁ is greater than 29 microFarads.
Page 167, the values in the table are changed due to the previous errors in the text.

Componenet	Desired Value	Obtainable Value
RE	1kOhm	1kOhm
RC	10kOhm	10kOhm
R1	10.4kOhm	10kOhm
R2	1.11kOhm	1kOhm
C1	29muF	33muF
C2	3.2muF	3.3muF

Page 167, In the expresion for Z_out in the middle of the page, the last term should be R_E/beta and not R_C/beta.
Page 168, In figure 5.25, R₅ should be R₃.
Page 190, The second formula on this page should be I_C=beta * I_B.
Page 205, in Figure 6.11, the inputs to the op-amp are reversed. The inverting input should be on top. Related to the flip in the figure, the text above describing which inputs v₁ and v₂ go into needs to be reversed.
Page 205+206, the derivation for the output voltage of the differential amplifier has a number of problems. A cleaner derivation is as follows. First, we note that v_out=-R₂/R₁(v₁-v₂). The voltage at the non-inverting input is v₊=v₂R₂/(R₁+R₂). By our op-amp rule, the voltage at the inverting input is equal to this. The input at the inverting input is also given by v_-=v_out+(v₁-v_out)R₂/(R₁+R₂). These two expressions for v_- can be equated to yield v_out=-(R₂/R₁)(v₁-v₂).
Page 323, The solution to problem 1.16 sould be V_th=V₀ and R_th=R₂.
Page 324, the answers to 3.9(e) and 3.9(f) are reversed.

New errors

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